numpy.square

numpy.square(x, /, out=None, *, where=True, casting='same_kind', order='K', dtype=None, subok=True[, signature, extobj]) = <ufunc 'square'>

Return the element-wise square of the input.

Parameters:

x : array_like

Input data.

out : ndarray, None, or tuple of ndarray and None, optional

A location into which the result is stored. If provided, it must have a shape that the inputs broadcast to. If not provided or None, a freshly-allocated array is returned. A tuple (possible only as a keyword argument) must have length equal to the number of outputs.

where : array_like, optional

Values of True indicate to calculate the ufunc at that position, values of False indicate to leave the value in the output alone.

**kwargs

For other keyword-only arguments, see the ufunc docs.

Returns:

out : ndarray or scalar

Element-wise x*x, of the same shape and dtype as x. This is a scalar if x is a scalar.

See also

numpy.linalg.matrix_power, sqrt, power

Examples

>>> np.square([-1j, 1])
array([-1.-0.j,  1.+0.j])